Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The typical adult human brain has a mass of about 1.4 kg. What force does a full moon exert on such a brain when it is directly above with its center 378000 km away? (Mass of the moon = 7.34 × 10 22 kg)
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Identify the values needed to calculate the gravitational force using Newton's Law of Universal Gravitation. We have:
- Mass of the brain, m = 1.4 kg
- Mass of the moon, M = 7.34 × 10^{22} kg
- Distance, r = 378000 km = 378000 × 10^3 m = 3.78 × 10^{8} m.
Step 2: Use the formula for gravitational force:
$$ F = G \frac{m \cdot M}{r^2} $$
where G is the gravitational constant, approximately $ 6.674 \times 10^{-11} \ ext{N m}^2/\text{kg}^2 $.
Step 3: Substitute the values into the formula:
$$ F = 6.674 \times 10^{-11} \frac{1.4 \times 7.34 \times 10^{22}}{(3.78 \times 10^{8})^2} $$
Step 4: Calculate the denominator:
$$ (3.78 \times 10^{8})^2 = 1.42884 \times 10^{17} $$
Step 5: Substitute it back into the equation:
$$ F = 6.674 \times 10^{-11} \frac{1.4 \times 7.34 \times 10^{22}}{1.42884 \times 10^{17}} $$
Step 6: Calculate the numerator:
$$ 1.4 \times 7.34 \times 10^{22} = 10.276 \times 10^{22} \text{ kg m}^2/\text{s}^2 $$
Step 7: Plugging everything into the final equation gives:
$$ F = 6.674 \times 10^{-11} \frac{10.276 \times 10^{22}}{1.42884 \times 10^{17}} \approx 0.469 \text{ N} $$
Therefore, the force exerted by the moon on the brain is approximately 0.469 N, rounded off appropriately. Thus, the full answer is: F \approx 0.47 N.
- Mass of the brain, m = 1.4 kg
- Mass of the moon, M = 7.34 × 10^{22} kg
- Distance, r = 378000 km = 378000 × 10^3 m = 3.78 × 10^{8} m.
Step 2: Use the formula for gravitational force:
$$ F = G \frac{m \cdot M}{r^2} $$
where G is the gravitational constant, approximately $ 6.674 \times 10^{-11} \ ext{N m}^2/\text{kg}^2 $.
Step 3: Substitute the values into the formula:
$$ F = 6.674 \times 10^{-11} \frac{1.4 \times 7.34 \times 10^{22}}{(3.78 \times 10^{8})^2} $$
Step 4: Calculate the denominator:
$$ (3.78 \times 10^{8})^2 = 1.42884 \times 10^{17} $$
Step 5: Substitute it back into the equation:
$$ F = 6.674 \times 10^{-11} \frac{1.4 \times 7.34 \times 10^{22}}{1.42884 \times 10^{17}} $$
Step 6: Calculate the numerator:
$$ 1.4 \times 7.34 \times 10^{22} = 10.276 \times 10^{22} \text{ kg m}^2/\text{s}^2 $$
Step 7: Plugging everything into the final equation gives:
$$ F = 6.674 \times 10^{-11} \frac{10.276 \times 10^{22}}{1.42884 \times 10^{17}} \approx 0.469 \text{ N} $$
Therefore, the force exerted by the moon on the brain is approximately 0.469 N, rounded off appropriately. Thus, the full answer is: F \approx 0.47 N.
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